Hi Marina, I rebuilt the entire page and now everything seems to work again. I still do not know what the problem was. Maybe, as you said, something in my JavaScript code, although I copy and pasted most of the scripts from the old to the new page, or some relicts of previous trials - I worked and c...

Hi Marina, I tried to reproduce the error again right now but it seems that the page is not even loaded properly so it does not even get to the onDeviceReady() call on device ready (which then calls the listServiceExecute()). However, the public link is: http://appery.io/app/mobile-frame?src... I se...

I built the page based on the "Building a simple ToDo app with Appery.io Backend Services, part 2: working in offline mode" and the code that was provided with it. The only thing I changed is that I run a query service called a_list_service instead of a list service. It was all working fin...

Many thanks for both of your answers! Extremely helpful!

If I cannot access the counter, then there is no use in hijacking it. So it has got to be labels after all.

Hi, I am using a list service to retrieve a list of entries from my database and map them to a mobile list. In the response of the service I am mapping the ids of the entries to the counter value property of the list item (maybe not the most elegant solution but I do not want to use labels). What I ...

Hi Igor,

Sorry, I only just got round to actually try it out using the list service. It works like a charm!

THANK YOU!

Hi Igor, Thanks for the quick reply! I had a look at this post earlier but it is not quite what I am looking for. I would be interested in the step 1 he described and which worked for him, though, i.e. to retrieve all possible values from a column in my collection without duplicates. If my collectio...

Hi, Unfortunately, I am not very familiar with databases and I have been trying for a while now to get distinct values from a database collection. I was wondering if you could help me. In your database documentation it says I should query 'where={projectID}' to get the distinct values of a column. (...