Hello Egor,
Thank you for your support.
With this line, time is being displayed in following format.
04:11:50.491
How can i remove .491 and leave only hour:minutes:second.
Thank you in advance.
Ilya
Hello Egor,
Thank you for your support.
With this line, time is being displayed in following format.
04:11:50.491
How can i remove .491 and leave only hour:minutes:second.
Thank you in advance.
Ilya
Hello Ilya,
try next
return date_parts[2]+"/"+date_parts[1]+"/"+date_parts[0] + " - " + date[1].split(".")[0];
Hello Egor,
Thanks, thats works perfectly
If someone is looking JS code to format the Date and time dd/mm/yyyy - hh:mm:ss
var date = value.split(" ");
var date1 = date[0];
var date_parts = date1.split("-");
return date_parts[2]+"/"+date_parts[1]+"/"+date_parts[0]+ " - " + date[1].split(".")[0];
BR
Ilya
HI, I have similar but quite different problem
I want to show the name of the month
I did this
var date = value.split(" ");
var date1 = date[0];
var date_parts = date1.split("-");
var monthNames = ["January", "February", "March", "April", "May", "June",
"July", "August", "September", "October", "November", "December"
];
return date_parts[2]+" "+monthNames[date_parts[1]]+" "+date_parts[0];
but it gives me for example 04 undefined 2016
Any suggestions?
Hello Zhivko,
Please use JS below for that:
prevar monthNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"
];
var d = new Date(value);
return d.getDate() + " " + monthNames[d.getMonth()] + " " + d.getFullYear();/pre